replacing nodes and sub-trees

Hi,

I have an table where I use XML data type to store documents. The following is an example of original document:

<!ORIGINAL DOCUMENT>

<ABC>

<xyz>.....</xyz>

<xyz>.....</xyz>

<gef>.....</gef>

<qew>....</qew>

</ABC>

<!NEW DOCUMENT>

<ABC>

<xyz>.....</xyz>

<gef>.....</gef>

<reb>....</reb>

</ABC>

My question is how to update the original document so that the two previous instances of xyz tag are replaced by the new single xyz tag, the original gef tag is replaced by the new gef tag, and the reb tag is added to the original document as it is not not present in the original document. The qew will not be updated. I can do this using DOM but I am looking to accomplish this using xquery and xml dml. Is this possible ? I appreciate help on this.

Thanks

It sounds like your algorithm is

For each element name in the NEW document, delete all the elements of that name in the OLD document and insert the new element into the OLD document.

You could do this w/ XQuery DML by generating a DML statement based on the NEW document.

Replacing data in a string

Hi

I have a table with unique data in but it has been inputted, below is an example of the data

6331245073
638 535 0797
7023593578
ID Number 650 379 4428
OCA8 9F 32
ocb92w153
vh235704

I need to strip out the all letters and spaces so it will look like this:

6331245073
6385350797
7023593578
6503794428

ect....

Thanks

Rich

Hi Rich,

You need to create a scalar function to do this. Here is an example:
CREATE FUNCTION FormatString(@.input VARCHAR(100))
RETURNS VARCHAR(100)
AS
BEGIN
DECLARE
@.character CHAR(1),
@.newstring VARCHAR(100),
@.counter INT

SET @.counter = 0
SET @.newstring = ''

WHILE @.counter < LEN(@.input)
BEGIN
SET @.counter = @.counter + 1
SET @.character = SUBSTRING(@.input, @.counter, 1)

IF @.character >= '0' AND @.character <= '9'
SET @.newstring = @.newstring + @.character
END

RETURN @.newstring
END

You can call the function as follow (note the dbo. prefix):

SELECT dbo.FormatString('ID Number 650 379 4428' )
SELECT dbo.FormatString(fieldname) FROM tablename

Greetz,

Geert

Geert Verhoeven
Consultant @. Ausy Belgium

My Personal Blog

|||

Thanks Geert did the job

Rich

replacing Apostrophe

I’m trying to key the syntax for replacing the Apostrophe with double
Apostrophe and update table.
Example: Programmer’s with Programmer’’s
Here code for finding occurrences:
SELECT DEALNAME
FROM DLWKTABLE20060609
where dealname like '%['']%'
BUT how do I update:
Update dlwktable20060609
Set dealname = replace(dealname, ?,?)
where dealname like '%['']%'declare @.c varchar(50)
select @.c ='O''Brian'
select replace(@.c, '''',''') ,@.c
Then the update will be
Update dlwktable20060609
Set dealname = replace(dealname, '''',''')
where dealname like '%['']%'
Denis the SQL Menace
http://sqlservercode.blogspot.com/
Logger wrote:
> I'm trying to key the syntax for replacing the Apostrophe with double
> Apostrophe and update table.
> Example: Programmer's with Programmer''s
> Here code for finding occurrences:
> SELECT DEALNAME
> FROM DLWKTABLE20060609
> where dealname like '%['']%'
> BUT how do I update:
> Update dlwktable20060609
> Set dealname = replace(dealname, ?,?)
> where dealname like '%['']%'

Replacing a cursor

I am currently evaluating the performance of an application which relies heavily on cursors. Below is an code example. I am looking for some good performance gains, is this the best method of updating rows of data?

DECLARE @.PAlloc_TimeID as int
DECLARE @.PAlloc_UniqueID as int
DECLARE PAlloc CURSOR FOR
SELECT TimeID,
UniqueID
FROM #PMatch
GROUP BY TimeID, UniqueID
HAVING SUM(Active) > 1

OPEN PAlloc
FETCH NEXT FROM PAlloc INTO @.PAlloc_TimeID , @.PAlloc_UniqueID
WHILE (@.@.FETCH_STATUS = 0)
BEGIN

UPDATE P
SET Active = 0
FROM #PMatch P
WHERE P.TimeID = @.PAlloc_TimeID
AND P.UniqueID = @.PAlloc_UniqueID
AND P.ElementID > (
SELECT MIN(ElementID)
FROM #PMatch
WHERE TimeID = @.PAlloc_TimeID
AND UniqueID = @.PAlloc_UniqueID)

FETCH NEXT FROM PAlloc INTO @.PAlloc_TimeID , @.PAlloc_UniqueID
END
CLOSE PAlloc
DEALLOCATE PAlloc

Normally, using a CURSOR is NOT the best way to update data. (However, in a few situations, it may be necessary.)

A set based operation (UPDATE) is usually the 'best' way to update. Consider if your process above could be re-written as a single UPDATE statement, perhaps using one or more sub-queries. (It might be easier than you think.)

|||

Yes... Arnie is right, It can be replace with single Update

Statement. But if the Database is gigantic then Updating in a single statement

is not preferred.

|||

u'll be able to write this query in one (or more) update statement(s)...or use a case in update statement.... most of the times u wont need a sursor at all.... and i guess even for a large database in this is a better solution..., as cursor on a large table will block resources for long...

sql

Replacement of values within a string

Hi,
I would like to find out what function I would need to
call to replace characters other than asterisks (*) in a
string value.
For example, I have values in a column in a table like
********SFWE, *****100****, *****200****, *****300****,
and *****400****. I now want these values to be
represented as ********YYYY, *****YYY****, *****YYY****,
*****YYY****, respectively. I want all non-asterisks
value in the string to be replaced with 'Y'.
Thank you in advance,
bpdeeTake a look at CharIndex...
Rick
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee|||Hi Rick,
Thank you for your response. Although, I would not know
other than it is a non-asterisk value that is in the
string that I need to replace with the value of 'Y'. It
could be any alphanumeric value and any combination of it
that is in the string that I need to replace. It could
also be anywhere in the string.
Thanks,
bpdee
>--Original Message--
>Take a look at CharIndex...
>Rick
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>> Hi,
>> I would like to find out what function I would need to
>> call to replace characters other than asterisks (*) in a
>> string value.
>> For example, I have values in a column in a table like
>> ********SFWE, *****100****, *****200****, *****300****,
>> and *****400****. I now want these values to be
>> represented as ********YYYY, *****YYY****, *****YYY****,
>> *****YYY****, respectively. I want all non-asterisks
>> value in the string to be replaced with 'Y'.
>> Thank you in advance,
>> bpdee
>
>.
>|||You probably want to do something like this. I've got the first part of the
replace working, you can probably figure out the second part. You might
want to put this into a function...
The last column in the example is what you're after; the others are so you
can follow what I'm doing.
declare @.myfield varchar(100)
set @.myfield = '*****100****'
select CHARINDEX('*', @.myfield),
PATINDEX('%[^*]%', @.myfield)-1,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), -- you might want to
put 100 Y's into the string at the start - depending on what you expect to
have in your field
STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%[^*]%', @.myfield)-1,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee|||Hi Andre,
Thank you for your response. You are correct that the
second one is the one I need to solve my problem. I ran
the select statement against my database and it is
definitely closer to what I need. Although, the result is
actually the opposite of what I want. The result I got
is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
want to keep all asterisks and replace those in the string
value that is NOT an asterisk with 'Y'. How would I do
that using the select you sent me?
Thanks,
bpdee
>--Original Message--
>You probably want to do something like this. I've got
the first part of the
>replace working, you can probably figure out the second
part. You might
>want to put this into a function...
>The last column in the example is what you're after; the
others are so you
>can follow what I'm doing.
>declare @.myfield varchar(100)
>set @.myfield = '*****100****'
>select CHARINDEX('*', @.myfield),
> PATINDEX('%[^*]%', @.myfield)-1,
> RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), --
you might want to
>put 100 Y's into the string at the start - depending on
what you expect to
>have in your field
> STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%
[^*]%', @.myfield)-1,
>RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
>Andre
>
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>> Hi,
>> I would like to find out what function I would need to
>> call to replace characters other than asterisks (*) in a
>> string value.
>> For example, I have values in a column in a table like
>> ********SFWE, *****100****, *****200****, *****300****,
>> and *****400****. I now want these values to be
>> represented as ********YYYY, *****YYY****, *****YYY****,
>> *****YYY****, respectively. I want all non-asterisks
>> value in the string to be replaced with 'Y'.
>> Thank you in advance,
>> bpdee
>
>.
>|||Hi,
You can probably use ASCII function to determine the ASCII value of *...
CREATE TABLE #temp
(a1 int, a2 char(1), a3 char(1))
DECLARE @.position int, @.string char(12)
SET @.position = 1
SET @.string = '********SFWE'
WHILE @.position <= DATALENGTH(@.string)
BEGIN
INSERT INTO #temp SELECT ASCII(SUBSTRING(@.string, @.position, 1)) a1,
CHAR(ASCII(SUBSTRING(@.string, @.position, 1))) a2, 'Y' a3
SET @.position = @.position + 1
END
SELECT a2,a3 FROM #temp
WHERE a1 NOT IN( 42, 44, 32)
Now I guess you can figure out, how you can replace a2 with a3 and transform
them into columns...
Thanks
GYK
"bpdee" wrote:
> Hi Rick,
> Thank you for your response. Although, I would not know
> other than it is a non-asterisk value that is in the
> string that I need to replace with the value of 'Y'. It
> could be any alphanumeric value and any combination of it
> that is in the string that I need to replace. It could
> also be anywhere in the string.
> Thanks,
> bpdee
>
> >--Original Message--
> >Take a look at CharIndex...
> >
> >Rick
> >
> >"bpdee" <anonymous@.discussions.microsoft.com> wrote in
> message
> >news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> >> Hi,
> >>
> >> I would like to find out what function I would need to
> >> call to replace characters other than asterisks (*) in a
> >> string value.
> >>
> >> For example, I have values in a column in a table like
> >> ********SFWE, *****100****, *****200****, *****300****,
> >> and *****400****. I now want these values to be
> >> represented as ********YYYY, *****YYY****, *****YYY****,
> >> *****YYY****, respectively. I want all non-asterisks
> >> value in the string to be replaced with 'Y'.
> >>
> >> Thank you in advance,
> >> bpdee
> >
> >
> >.
> >
>|||Here is some code that should work...
You could make this into a sproc or a function...
DECLARE @.OrgCol varchar(100)
@.Count int,
@.NewCol varchar(100)
SELECT @.OrgCol = ColumnName FROM TableName
SET @.Count = 1
SET @.NewCol = ''
WHILE (@.Count < DATALENGTH(@.OrgCol))
BEGIN
IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
SET @.NewCol = @.NewCol + 'Y'
ELSE
SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
SET @.Count = @.Count + 1
END
-- Write your update statement here or return @.NewCol if a UDF
Rick Sawtell
MCT, MCSD, MCDBA|||Sorry, I didn't read well enough. :)
While I still think functions are efficient and might be a good thing to
use, if I can accomplish what I want in a query, I'll generally pick that
route first. That said, give this a whirl. It worked for me regardless of
whether or not there were asterisks at the beginning or end of the string,
and no matter how many there were. The reason I'd opt for a function is
this isn't very intuitive to understand when you look at it, and you can
probably take a more intuitive approach in a function, like the examples
that have been given by others here.
declare @.myfield varchar(100)
set @.myfield = '******SFWE'
select STUFF(@.myfield, PATINDEX('%[^*]%', @.myfield), 4, RIGHT('YYYYYYYYYY',
(LEN(@.myfield) - ((PATINDEX('%[^*]%', @.myfield)-1) + (PATINDEX('%[^*]%',
REVERSE(@.myfield))-1)))))
I hope this helps.
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:155701c4b627$8638b6a0$a501280a@.phx.gbl...
> Hi Andre,
> Thank you for your response. You are correct that the
> second one is the one I need to solve my problem. I ran
> the select statement against my database and it is
> definitely closer to what I need. Although, the result is
> actually the opposite of what I want. The result I got
> is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
> want to keep all asterisks and replace those in the string
> value that is NOT an asterisk with 'Y'. How would I do
> that using the select you sent me?
> Thanks,
> bpdee
>>--Original Message--
>>You probably want to do something like this. I've got
> the first part of the
>>replace working, you can probably figure out the second
> part. You might
>>want to put this into a function...
>>The last column in the example is what you're after; the
> others are so you
>>can follow what I'm doing.
>>declare @.myfield varchar(100)
>>set @.myfield = '*****100****'
>>select CHARINDEX('*', @.myfield),
>> PATINDEX('%[^*]%', @.myfield)-1,
>> RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), --
> you might want to
>>put 100 Y's into the string at the start - depending on
> what you expect to
>>have in your field
>> STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%
> [^*]%', @.myfield)-1,
>>RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
>>Andre
>>
>>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
> message
>>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>> Hi,
>> I would like to find out what function I would need to
>> call to replace characters other than asterisks (*) in a
>> string value.
>> For example, I have values in a column in a table like
>> ********SFWE, *****100****, *****200****, *****300****,
>> and *****400****. I now want these values to be
>> represented as ********YYYY, *****YYY****, *****YYY****,
>> *****YYY****, respectively. I want all non-asterisks
>> value in the string to be replaced with 'Y'.
>> Thank you in advance,
>> bpdee
>>
>>.|||Hi Rick,
Thank you so much, Rick! This did the trick.
Thanks again,
Bettina
"Rick Sawtell" wrote:
> Here is some code that should work...
> You could make this into a sproc or a function...
> DECLARE @.OrgCol varchar(100)
> @.Count int,
> @.NewCol varchar(100)
> SELECT @.OrgCol = ColumnName FROM TableName
> SET @.Count = 1
> SET @.NewCol = ''
> WHILE (@.Count < DATALENGTH(@.OrgCol))
> BEGIN
> IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
> SET @.NewCol = @.NewCol + 'Y'
> ELSE
> SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
> SET @.Count = @.Count + 1
> END
> -- Write your update statement here or return @.NewCol if a UDF
>
> Rick Sawtell
> MCT, MCSD, MCDBA
>
>

Replacement of values within a string

Hi,
I would like to find out what function I would need to
call to replace characters other than asterisks (*) in a
string value.
For example, I have values in a column in a table like
********SFWE, *****100****, *****200****, *****300****,
and *****400****. I now want these values to be
represented as ********YYYY, *****YYY****, *****YYY****,
*****YYY****, respectively. I want all non-asterisks
value in the string to be replaced with 'Y'.
Thank you in advance,
bpdee
Take a look at CharIndex...
Rick
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee
|||Hi Rick,
Thank you for your response. Although, I would not know
other than it is a non-asterisk value that is in the
string that I need to replace with the value of 'Y'. It
could be any alphanumeric value and any combination of it
that is in the string that I need to replace. It could
also be anywhere in the string.
Thanks,
bpdee

>--Original Message--
>Take a look at CharIndex...
>Rick
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>
>.
>
|||You probably want to do something like this. I've got the first part of the
replace working, you can probably figure out the second part. You might
want to put this into a function...
The last column in the example is what you're after; the others are so you
can follow what I'm doing.
declare @.myfield varchar(100)
set @.myfield = '*****100****'
select CHARINDEX('*', @.myfield),
PATINDEX('%[^*]%', @.myfield)-1,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), -- you might want to
put 100 Y's into the string at the start - depending on what you expect to
have in your field
STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%[^*]%', @.myfield)-1,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee
|||Hi Andre,
Thank you for your response. You are correct that the
second one is the one I need to solve my problem. I ran
the select statement against my database and it is
definitely closer to what I need. Although, the result is
actually the opposite of what I want. The result I got
is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
want to keep all asterisks and replace those in the string
value that is NOT an asterisk with 'Y'. How would I do
that using the select you sent me?
Thanks,
bpdee

>--Original Message--
>You probably want to do something like this. I've got
the first part of the
>replace working, you can probably figure out the second
part. You might
>want to put this into a function...
>The last column in the example is what you're after; the
others are so you
>can follow what I'm doing.
>declare @.myfield varchar(100)
>set @.myfield = '*****100****'
>select CHARINDEX('*', @.myfield),
> PATINDEX('%[^*]%', @.myfield)-1,
> RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), --
you might want to
>put 100 Y's into the string at the start - depending on
what you expect to
>have in your field
> STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%
[^*]%', @.myfield)-1,
>RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
>Andre
>
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>
>.
>
|||Hi,
You can probably use ASCII function to determine the ASCII value of *...
CREATE TABLE #temp
(a1 int, a2 char(1), a3 char(1))
DECLARE @.position int, @.string char(12)
SET @.position = 1
SET @.string = '********SFWE'
WHILE @.position <= DATALENGTH(@.string)
BEGIN
INSERT INTO #temp SELECT ASCII(SUBSTRING(@.string, @.position, 1)) a1,
CHAR(ASCII(SUBSTRING(@.string, @.position, 1))) a2, 'Y' a3
SET @.position = @.position + 1
END
SELECT a2,a3 FROM #temp
WHERE a1 NOT IN( 42, 44, 32)
Now I guess you can figure out, how you can replace a2 with a3 and transform
them into columns...
Thanks
GYK
"bpdee" wrote:

> Hi Rick,
> Thank you for your response. Although, I would not know
> other than it is a non-asterisk value that is in the
> string that I need to replace with the value of 'Y'. It
> could be any alphanumeric value and any combination of it
> that is in the string that I need to replace. It could
> also be anywhere in the string.
> Thanks,
> bpdee
>
> message
>
|||Here is some code that should work...
You could make this into a sproc or a function...
DECLARE @.OrgCol varchar(100)
@.Count int,
@.NewCol varchar(100)
SELECT @.OrgCol = ColumnName FROM TableName
SET @.Count = 1
SET @.NewCol = ''
WHILE (@.Count < DATALENGTH(@.OrgCol))
BEGIN
IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
SET @.NewCol = @.NewCol + 'Y'
ELSE
SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
SET @.Count = @.Count + 1
END
-- Write your update statement here or return @.NewCol if a UDF
Rick Sawtell
MCT, MCSD, MCDBA
|||Sorry, I didn't read well enough.
While I still think functions are efficient and might be a good thing to
use, if I can accomplish what I want in a query, I'll generally pick that
route first. That said, give this a whirl. It worked for me regardless of
whether or not there were asterisks at the beginning or end of the string,
and no matter how many there were. The reason I'd opt for a function is
this isn't very intuitive to understand when you look at it, and you can
probably take a more intuitive approach in a function, like the examples
that have been given by others here.
declare @.myfield varchar(100)
set @.myfield = '******SFWE'
select STUFF(@.myfield, PATINDEX('%[^*]%', @.myfield), 4, RIGHT('YYYYYYYYYY',
(LEN(@.myfield) - ((PATINDEX('%[^*]%', @.myfield)-1) + (PATINDEX('%[^*]%',
REVERSE(@.myfield))-1)))))
I hope this helps.
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:155701c4b627$8638b6a0$a501280a@.phx.gbl...[vbcol=seagreen]
> Hi Andre,
> Thank you for your response. You are correct that the
> second one is the one I need to solve my problem. I ran
> the select statement against my database and it is
> definitely closer to what I need. Although, the result is
> actually the opposite of what I want. The result I got
> is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
> want to keep all asterisks and replace those in the string
> value that is NOT an asterisk with 'Y'. How would I do
> that using the select you sent me?
> Thanks,
> bpdee
> the first part of the
> part. You might
> others are so you
> you might want to
> what you expect to
> [^*]%', @.myfield)-1,
> message
|||Hi Rick,
Thank you so much, Rick! This did the trick.
Thanks again,
Bettina
"Rick Sawtell" wrote:

> Here is some code that should work...
> You could make this into a sproc or a function...
> DECLARE @.OrgCol varchar(100)
> @.Count int,
> @.NewCol varchar(100)
> SELECT @.OrgCol = ColumnName FROM TableName
> SET @.Count = 1
> SET @.NewCol = ''
> WHILE (@.Count < DATALENGTH(@.OrgCol))
> BEGIN
> IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
> SET @.NewCol = @.NewCol + 'Y'
> ELSE
> SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
> SET @.Count = @.Count + 1
> END
> -- Write your update statement here or return @.NewCol if a UDF
>
> Rick Sawtell
> MCT, MCSD, MCDBA
>
>

Replacement of values within a string

Hi,
I would like to find out what function I would need to
call to replace characters other than asterisks (*) in a
string value.
For example, I have values in a column in a table like
********SFWE, *****100****, *****200****, *****300****,
and *****400****. I now want these values to be
represented as ********YYYY, *****YYY****, *****YYY****,
*****YYY****, respectively. I want all non-asterisks
value in the string to be replaced with 'Y'.
Thank you in advance,
bpdeeTake a look at CharIndex...
Rick
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee|||Hi Rick,
Thank you for your response. Although, I would not know
other than it is a non-asterisk value that is in the
string that I need to replace with the value of 'Y'. It
could be any alphanumeric value and any combination of it
that is in the string that I need to replace. It could
also be anywhere in the string.
Thanks,
bpdee

>--Original Message--
>Take a look at CharIndex...
>Rick
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>
>.
>|||You probably want to do something like this. I've got the first part of the
replace working, you can probably figure out the second part. You might
want to put this into a function...
The last column in the example is what you're after; the others are so you
can follow what I'm doing.
declare @.myfield varchar(100)
set @.myfield = '*****100****'
select CHARINDEX('*', @.myfield),
PATINDEX('%[^*]%', @.myfield)-1,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), -- you might want t
o
put 100 Y's into the string at the start - depending on what you expect to
have in your field
STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%[^*]%', @.myfield)-1
,
RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
> Hi,
> I would like to find out what function I would need to
> call to replace characters other than asterisks (*) in a
> string value.
> For example, I have values in a column in a table like
> ********SFWE, *****100****, *****200****, *****300****,
> and *****400****. I now want these values to be
> represented as ********YYYY, *****YYY****, *****YYY****,
> *****YYY****, respectively. I want all non-asterisks
> value in the string to be replaced with 'Y'.
> Thank you in advance,
> bpdee|||Hi Andre,
Thank you for your response. You are correct that the
second one is the one I need to solve my problem. I ran
the select statement against my database and it is
definitely closer to what I need. Although, the result is
actually the opposite of what I want. The result I got
is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
want to keep all asterisks and replace those in the string
value that is NOT an asterisk with 'Y'. How would I do
that using the select you sent me?
Thanks,
bpdee

>--Original Message--
>You probably want to do something like this. I've got
the first part of the
>replace working, you can probably figure out the second
part. You might
>want to put this into a function...
>The last column in the example is what you're after; the
others are so you
>can follow what I'm doing.
>declare @.myfield varchar(100)
>set @.myfield = '*****100****'
>select CHARINDEX('*', @.myfield),
> PATINDEX('%[^*]%', @.myfield)-1,
> RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1), --
you might want to
>put 100 Y's into the string at the start - depending on
what you expect to
>have in your field
> STUFF(@.myfield, CHARINDEX('*', @.myfield), PATINDEX('%
[^*]%', @.myfield)-1,
>RIGHT('YYYYYYYYYY', PATINDEX('%[^*]%', @.myfield)-1))
>Andre
>
>"bpdee" <anonymous@.discussions.microsoft.com> wrote in
message
>news:150301c4b61a$0be52cb0$a501280a@.phx.gbl...
>
>.
>|||Hi,
You can probably use ASCII function to determine the ASCII value of *...
CREATE TABLE #temp
(a1 int, a2 char(1), a3 char(1))
DECLARE @.position int, @.string char(12)
SET @.position = 1
SET @.string = '********SFWE'
WHILE @.position <= DATALENGTH(@.string)
BEGIN
INSERT INTO #temp SELECT ASCII(SUBSTRING(@.string, @.position, 1)) a1,
CHAR(ASCII(SUBSTRING(@.string, @.position, 1))) a2, 'Y' a3
SET @.position = @.position + 1
END
SELECT a2,a3 FROM #temp
WHERE a1 NOT IN( 42, 44, 32)
Now I guess you can figure out, how you can replace a2 with a3 and transform
them into columns...
Thanks
GYK
"bpdee" wrote:

> Hi Rick,
> Thank you for your response. Although, I would not know
> other than it is a non-asterisk value that is in the
> string that I need to replace with the value of 'Y'. It
> could be any alphanumeric value and any combination of it
> that is in the string that I need to replace. It could
> also be anywhere in the string.
> Thanks,
> bpdee
>
> message
>|||Here is some code that should work...
You could make this into a sproc or a function...
DECLARE @.OrgCol varchar(100)
@.Count int,
@.NewCol varchar(100)
SELECT @.OrgCol = ColumnName FROM TableName
SET @.Count = 1
SET @.NewCol = ''
WHILE (@.Count < DATALENGTH(@.OrgCol))
BEGIN
IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
SET @.NewCol = @.NewCol + 'Y'
ELSE
SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
SET @.Count = @.Count + 1
END
-- Write your update statement here or return @.NewCol if a UDF
Rick Sawtell
MCT, MCSD, MCDBA|||Sorry, I didn't read well enough.
While I still think functions are efficient and might be a good thing to
use, if I can accomplish what I want in a query, I'll generally pick that
route first. That said, give this a whirl. It worked for me regardless of
whether or not there were asterisks at the beginning or end of the string,
and no matter how many there were. The reason I'd opt for a function is
this isn't very intuitive to understand when you look at it, and you can
probably take a more intuitive approach in a function, like the examples
that have been given by others here.
declare @.myfield varchar(100)
set @.myfield = '******SFWE'
select STUFF(@.myfield, PATINDEX('%[^*]%', @.myfield), 4, RIGHT('YYYYYYYYY
Y',
(LEN(@.myfield) - ((PATINDEX('%[^*]%', @.myfield)-1) + (PATINDEX('%[^*
]%',
REVERSE(@.myfield))-1)))))
I hope this helps.
Andre
"bpdee" <anonymous@.discussions.microsoft.com> wrote in message
news:155701c4b627$8638b6a0$a501280a@.phx.gbl...[vbcol=seagreen]
> Hi Andre,
> Thank you for your response. You are correct that the
> second one is the one I need to solve my problem. I ran
> the select statement against my database and it is
> definitely closer to what I need. Although, the result is
> actually the opposite of what I want. The result I got
> is 'YYYYYYYYSFWE' while I wanted is '********YYYY'. I
> want to keep all asterisks and replace those in the string
> value that is NOT an asterisk with 'Y'. How would I do
> that using the select you sent me?
> Thanks,
> bpdee
>
> the first part of the
> part. You might
> others are so you
> you might want to
> what you expect to
> [^*]%', @.myfield)-1,
> message|||Hi Rick,
Thank you so much, Rick! This did the trick.
Thanks again,
Bettina
"Rick Sawtell" wrote:

> Here is some code that should work...
> You could make this into a sproc or a function...
> DECLARE @.OrgCol varchar(100)
> @.Count int,
> @.NewCol varchar(100)
> SELECT @.OrgCol = ColumnName FROM TableName
> SET @.Count = 1
> SET @.NewCol = ''
> WHILE (@.Count < DATALENGTH(@.OrgCol))
> BEGIN
> IF (SUBSTRING(@.OrgCol, @.Count, 1) <> '*')
> SET @.NewCol = @.NewCol + 'Y'
> ELSE
> SET @.NewCol = @.NewCol + SUBSTRING(@.OrgCol, @.Count, 1)
> SET @.Count = @.Count + 1
> END
> -- Write your update statement here or return @.NewCol if a UDF
>
> Rick Sawtell
> MCT, MCSD, MCDBA
>
>

REPLACE SUBSTRING BETWEEN TWO CHARACTERS

Hi.
I have to replace substrings which are between two characters.
For example: I have to replace or remove all the characters that are
between ' \':
So, i have the string abcde\fgh\ikl and i want to get: abcdeikl.
I use the following select statement:
REPLACE(ColumnName, SUBSTRING([ColumnName, CHARINDEX('\', ColumnName),
CHARINDEX('\', ColumnName, CHARINDEX('\', ColumnName) + 1) -
CHARINDEX('\', ColumnName + 1), '')
Is there any more efficient way?
Thanks.Hi
declare @.d varchar(50)
set @.d='abkcde\fgh\ikl'
select STUFF(@.d,start,endpos-start,'')
from
(
select charindex('',@.d,1) as start,
len(@.d)-charindex('',reverse(@.d),1)+2 as endpos
) as der
<stelioshalkiotis@.yahoo.gr> wrote in message
news:1132833870.358155.145790@.g47g2000cwa.googlegroups.com...
> Hi.
> I have to replace substrings which are between two characters.
> For example: I have to replace or remove all the characters that are
> between ' ':
> So, i have the string abcde\fgh\ikl and i want to get: abcdeikl.
> I use the following select statement:
> REPLACE(ColumnName, SUBSTRING([ColumnName, CHARINDEX('', ColumnName),
> CHARINDEX('', ColumnName, CHARINDEX('', ColumnName) + 1) -
> CHARINDEX('', ColumnName + 1), '')
> Is there any more efficient way?
> Thanks.
>|||or
declare @.d varchar(50)
set @.d='abkcde\fgh\ikl'
Select
Substring(@.d,1,charindex('\',@.d)- 1)+reverse(Substring(reverse(@.d),1,chari
nde
x('\',reverse(@.d))-1))
Madhivanan

Replace or Subtract string

I have 2 columns being pulled in from mssql and need only a portion of
one column listed, for example I have:
Col1 Col2
--
--
BUILTIN_Administrators_master BUILTIN_Administrators_
sa_master sa_
DBA_msdb DBA_
...etc
I would like to, for lack of a better word, subtract column 2 from 1 to
leave "master", "msdb", etc.
Is this possible with SRS, and if so how?
Apparently I am new to this and not very skilled with the programming
aspect either, still learning. So any help would be appreciated.Got it using:
=Replace( Fields!path_leaf.Value, Fields!New.Value,"")sql

replace missing data

I am working with a database containing time series data. In many, cases there is missing data. For example, while there might be a value for 2001-01-01T23:00:00, there is none for 2001-01-01T23:0100 (one minute later). I would like to replace the missing data with data from the previous record (if the previous record is the same date). Is that possible with T-SQL?

Sure,

UPDATE SomeTable
FROM SomeTable ST
SET SomeColumnWhereDataisMissing =
(
Select TOP (1) SomeColumn From SomeTable ST2
WHERE ST2.TimeColumn < ST.TimeColumn
)
WHERE SomeColumnWhereDataisMissing IS NULL --Or whatever means that there is no data.

HTH, Jens Suessmeyer.

http://www.sqlserver2005.de

|||

Missing means there is no record for a specific datetime value. There is no null because the record does not exist.

|||

It sounds like you're looking for a list of missing dates. You can use an auxiliary numbers table to generate a list of dates and perform an OUTER JOIN against the table in question.

The following sample uses a table with one entry for each minute in a day. To me, it seems best to loop through this table on a daily basis rather than to create a date-only table that would be specific to your problem.

-- Create numbers table. You want this as a permanent table but I'm generating on-the-fly for this example.

DECLARE @.Nums TABLE (Val INT)

;WITH Numbers(n)

AS

(

SELECT 1 AS n

UNION ALL

SELECT (n + 1) AS n

FROM Numbers

WHERE

n < 1440 -- Minutes in a day

)

INSERT INTO @.Nums (Val)

SELECT n from Numbers

OPTION(MAXRECURSION 1440)

-- Create sample data

DECLARE @.Dates TABLE (PKey INT IDENTITY PRIMARY KEY, MyDate DATETIME)

INSERT INTO @.Dates (MyDate)

SELECT '2006-08-21 13:21:00'

UNION

SELECT '2006-08-21 13:22:00'

UNION

SELECT '2006-08-21 13:23:00'

UNION

SELECT '2006-08-21 13:25:00'

UNION

SELECT '2006-08-21 13:26:00'

UNION

SELECT '2006-08-21 13:30:00'

-

-- Find missing ranges.

-

DECLARE @.MinMinute INT

DECLARE @.MaxMinute INT

DECLARE @.CheckDate DATETIME -- This is the day that we're checking

SET @.CheckDate = '2006-08-21'

-- First and last time for the day of @.CheckDate

SELECT @.MinMinute = DATEDIFF(minute, @.CheckDate, MIN(MyDate)),

@.MaxMinute = DATEDIFF(minute, @.CheckDate, MAX(MyDate))

FROM @.Dates

WHERE MyDate BETWEEN @.CheckDate AND DATEADD(Day, 1, @.CheckDate)

-- Find all missing minutes in the sequence

SELECT DATEADD(minute, n.Val, @.CheckDate) AS MissingMinute, 'Missing' AS Status

FROM @.Nums n

LEFT JOIN @.Dates d ON DATEADD(minute, n.Val, @.CheckDate) = d.MyDate

WHERE n.Val BETWEEN @.MinMinute AND @.MaxMinute

and d.MyDate IS NULL

UNION ALL

SELECT MyDate, 'Exists' AS Status

FROM @.Dates

ORDER BY MissingMinute

Thanks to the following sources for information regarding auxiliary numbers tables

http://sqlserver2000.databases.aspfaq.com/why-should-i-consider-using-an-auxiliary-numbers-table.html

http://codeinet.blogspot.com/2006/06/sql-numbers-table-using-common-table.html

|||

Slight edit - the previous code to generate an auxiliary numbers table will only work on SQL Server 2005. Use the following for SQL 2000:

CREATE TABLE dbo.Numbers
(
Number INT IDENTITY(1,1) PRIMARY KEY CLUSTERED
)
WHILE COALESCE(SCOPE_IDENTITY(), 0) <= 1440
BEGIN
INSERT dbo.Numbers DEFAULT VALUES
END

replace a part of a string in a Table

hey,

I have a lage table with 1000's of records..
there is a column with the path to some files.

example: "R:\mutaties\test.pdf"

i need to change that path to "L:\archive\mutaties\test.pdf"

i will replace "R:\" with "L:\archive\" in all the records.. what;'s the simpelst way tot do this?

can i do a replace with SQL-queries? , or do i need to write a code/script for this?

grtz,
Blueupdate LargeTable
set Column = 'L:\archive' + substring(Column, 3, length(Column) - 3)
where Column like 'R:\%'|||Thanx Pierre ;)

I will try it :D

Repeat details section if

Is there a way to make the details section repeat depending on the quantity that is associated with a record. For example we have a product and if the customer orders more then one we want the sticker to print out twice. I am running crystal reports 8.
Thanks
DaveYou can set the number of copies to print , depending on the quantity|||How do you generate report?
If you generate it on customerwise, thru coding you need to check the number of records it prints and accordingly set print copies